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5x^2+70x=245
We move all terms to the left:
5x^2+70x-(245)=0
a = 5; b = 70; c = -245;
Δ = b2-4ac
Δ = 702-4·5·(-245)
Δ = 9800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9800}=\sqrt{4900*2}=\sqrt{4900}*\sqrt{2}=70\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-70\sqrt{2}}{2*5}=\frac{-70-70\sqrt{2}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+70\sqrt{2}}{2*5}=\frac{-70+70\sqrt{2}}{10} $
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